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4v^2+24v+11=0
a = 4; b = 24; c = +11;
Δ = b2-4ac
Δ = 242-4·4·11
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-20}{2*4}=\frac{-44}{8} =-5+1/2 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+20}{2*4}=\frac{-4}{8} =-1/2 $
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